The aim of our lab was to determine the specific heat of copper and to compare with the actual result and then find the experimental error.

Specific Heat Labhttp://honolulu.hawaii.edu/distance/sci122/Programs/p21/image.gifAim:Specific rouse is the kernel of transform per mass required to raise the temperature of 1ºC. unlike materials lease different unique(predicate) passions. The aim of our lab was to determine the precise awaken of blur and to compare with the actual result by finding the experimental error. Materials and equipment:Electrical balanceWaterCalorimeterCylinder of copperThermometerBeakerHotplateCrucible tongsGraduated cylinderGogglesObservations:We started off the lab by filling our calorimeter with 100 cm³ of water from the tap. We recorded the initial temperature into our chart and continued to work. We took the cylindrical copper and put it into the beaker change with water. Our goal was to rise the temperature of the water to 100ºC. After spectacular the goal we pulled out the metallic element and carefully dropped it into the calorimeter. We watched the temperature going from 26/24 u p to 28/27. After collecting all(prenominal) told the needed information we plugged in our results into the specific heat formula:Then we made the specific heat of copper ? X and solved the equation. Calculations:Heat gained by the waterHeat lost by the metalMass of water ? 100 Mass of metal (m) ? 57.04Initial temperature of water - 26ºCInitial temperature of metal - 96ºCFinal temperature of mixture - 28ºCFinal temperature of mixture - 28ºCT - 2 T ? 58ºC1st metre100*4.184(28-26) = (96-28)*X*57.04418.4*2 = 58*57.04X836.8 = 3878.72X836.8/3878.72 = X0.216 = XSpecific heat ? 0.

216 JActual specific heat ? 0.385 JExp. Error :(0.385-0.216)/0.385*10044% errorHeat gained! by the waterHeat lost by the metalMass of water ? 100 Mass of metal (m) ? 57.04Initial temperature of water - 24ºCInitial temperature of metal - 97ºCFinal temperature of mixture - 27ºCFinal temperature of mixture - 27ºCT - 3 T ? 702nd cartridge clip:100*4.184(27-24) = (97-27)*X*57.04418.4*3 = 70*X*57.041255.2 = 3992.8X1255.2/3992.8 = X0.314 = XSpecific heat ? 0.314 JActual specific heat ? 0.385 J(0.385-0.314)/0.385*10017% errorConclusion:Specific heat is the amount... If you want to go away a full essay, order it on our website: OrderCustomPaper.com

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